2x^2-1.4x+0.1=0

Solution for 2x^2-1.4x+0.1=0 equation:

2x^2-1.4x+0.1=0

a = 2; b = -1.4; c = +0.1;
Δ = b2-4ac
Δ = -1.42-4·2·0.1
Δ = 1.16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.4)-\sqrt{1.16}}{2*2}=\frac{1.4-\sqrt{1.16}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.4)+\sqrt{1.16}}{2*2}=\frac{1.4+\sqrt{1.16}}{4}
$